What is the integral from 1 to 2 of (xe^x)/y ?

The integral from 1 to 2 of (xe^x)/y is xe^xln(2)

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integral from 1 to 2 of (xe^x)/y

\int_{1}^{2} \frac{x e ^{x}}{y} d y

x e^{x} ln (2)

Solution steps

\int_{1}^{2} \frac{x e ^{x}}{y} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= x e^{x} \cdot \int_{1}^{2} \frac{1}{y} d y

Use the common integral:

\int \frac{1}{y} d y = ln (∣ y ∣)

= x e^{x} [ln ∣ y ∣]_{1}^{2}

Compute the boundaries:

ln (2)

= x e^{x} ln (2)

What is the integral from 1 to 2 of (xe^x)/y ?
The integral from 1 to 2 of (xe^x)/y is xe^xln(2)