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Popular Calculus >

integral of integral of 1

Solution

\int \int 1 d x d x

Solution

\frac{x ^{2}}{2} + C x + C

Solution steps

\int \int 1 d x d x

\int 1 d x = x + C

= \int (x + C) d x

\int (x + C) d x = \frac{x ^{2}}{2} + C x + C

= \frac{x ^{2}}{2} + C x + C

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Frequently Asked Questions (FAQ)

What is the integral of integral of 1 ?
The integral of integral of 1 is (x^2)/2+Cx+C