What is the integral of integral of-1/x ?

The integral of integral of-1/x is x(-ln(x)+C)+x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of integral of-1/x

\int \int - \frac{1}{x} d x d x

x (- ln (x) + C) + x + C

Solution steps

\int \int - \frac{1}{x} d x d x

\int - \frac{1}{x} d x = - ln (x) + C

= \int (- ln (x) + C) d x

\int (- ln (x) + C) d x = x (- ln (x) + C) + x + C

= x (- ln (x) + C) + x + C

What is the integral of integral of-1/x ?
The integral of integral of-1/x is x(-ln(x)+C)+x+C