What is the solution for 7y^{''}+13y^'-2y=0 ?

The solution for 7y^{''}+13y^'-2y=0 is y=c_{1}e^{t/7}+c_{2}e^{-2t}

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7y^{''}+13y^'-2y=0

7 y^{^{''}} + 13 y^{^{'}} - 2 y = 0

y = c_{1} e^{\frac{t}{7}} + c_{2} e^{- 2 t}

Solution steps

7 y^{''} (t) + 13 y^{'} (t) - 2 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{7}} + c_{2} e^{- 2 t}

y = c_{1} e^{\frac{t}{7}} + c_{2} e^{- 2 t}

What is the solution for 7y^{''}+13y^'-2y=0 ?
The solution for 7y^{''}+13y^'-2y=0 is y=c_{1}e^{t/7}+c_{2}e^{-2t}