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人気のある微分積分 >

derivative f(t)=e^{7tsin(2t)}

解

導関数

f (t) = e^{7 t s i n (2 t)}

解

e^{7 t s i n (2 t)} \cdot 7 (sin (2 t) + 2 t cos (2 t))

解答ステップ

\frac{d}{d t} (e^{7 t s i n (2 t)})

連鎖法則を適用:

e^{7 t s i n (2 t)} \frac{d}{d t} (7 t sin (2 t))

= e^{7 t s i n (2 t)} \frac{d}{d t} (7 t sin (2 t))

\frac{d}{d t} (7 t sin (2 t)) = 7 (sin (2 t) + 2 t cos (2 t))

= e^{7 t s i n (2 t)} \cdot 7 (sin (2 t) + 2 t cos (2 t))

グラフ

人気の例

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