What is (\partial)/(\partial x)(4x+cy+2z) ?

The answer to (\partial)/(\partial x)(4x+cy+2z) is 4

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(\partial)/(\partial x)(4x+cy+2z)

\frac{\partial}{\partial x} (4 x + cy + 2 z)

4

Solution steps

\frac{\partial}{\partial x} (4 x + cy + 2 z)

Treat

c, y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x) + \frac{\partial}{\partial x} (cy) + \frac{\partial}{\partial x} (2 z)

\frac{\partial}{\partial x} (4 x) = 4

\frac{\partial}{\partial x} (cy) = 0

\frac{\partial}{\partial x} (2 z) = 0

= 4 + 0 + 0

Simplify

= 4

What is (\partial)/(\partial x)(4x+cy+2z) ?
The answer to (\partial)/(\partial x)(4x+cy+2z) is 4