What is the derivative of x^3-8x^2+19x-12 ?

The derivative of x^3-8x^2+19x-12 is 3x^2-16x+19

What is the first derivative of x^3-8x^2+19x-12 ?

The first derivative of x^3-8x^2+19x-12 is 3x^2-16x+19

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derivative of

x^{3} - 8 x^{2} + 19 x - 12

3 x^{2} - 16 x + 19

Solution steps

\frac{d}{d x} (x^{3} - 8 x^{2} + 19 x - 12)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (8 x^{2}) + \frac{d}{d x} (19 x) - \frac{d}{d x} (12)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (8 x^{2}) = 16 x

\frac{d}{d x} (19 x) = 19

\frac{d}{d x} (12) = 0

= 3 x^{2} - 16 x + 19 - 0

Simplify

= 3 x^{2} - 16 x + 19

What is the derivative of x^3-8x^2+19x-12 ?
The derivative of x^3-8x^2+19x-12 is 3x^2-16x+19
What is the first derivative of x^3-8x^2+19x-12 ?
The first derivative of x^3-8x^2+19x-12 is 3x^2-16x+19