What is the limit as x approaches 4 of (x^2-8x+16)/(x-4) ?

The limit as x approaches 4 of (x^2-8x+16)/(x-4) is 0

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limit as x approaches 4 of (x^2-8x+16)/(x-4)

x \to 4 lim (\frac{x ^{2} - 8 x + 16}{x - 4})

0

Solution steps

x \to 4 lim (\frac{x ^{2} - 8 x + 16}{x - 4})

Simplify

\frac{x ^{2} - 8 x + 16}{x - 4} : x - 4

= x \to 4 lim (x - 4)

Plug in the value

x = 4

= 4 - 4

Simplify

= 0

What is the limit as x approaches 4 of (x^2-8x+16)/(x-4) ?
The limit as x approaches 4 of (x^2-8x+16)/(x-4) is 0