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人気のある微分積分 >

limit as x approaches 0 of (2^x+x)^{1/x}

解

x \to 0 lim ((2^{x} + x)^{\frac{1}{x}})

解

2 e

+1

十進法表記

5.43656 \dots

解答ステップ

x \to 0 lim ((2^{x} + x)^{\frac{1}{x}})

指数の規則を適用する

= x \to 0 lim (e^{\frac{1}{x} l n (2^{x} + x)})

連鎖法則の制限を適用する:

2 e

= 2 e

グラフ

人気の例

limit as x approaches 0+of ln((x+1)^x)

x \to 0 + lim (ln ((x + 1)^{x}))

limit as x approaches 1+of ln(x)ln(x-1)

x \to 1 + lim (ln (x) ln (x - 1))

limit as x approaches 4 of 3(x-4)^{x-4}

x \to 4 lim (3 (x - 4)^{x - 4})

limit as x approaches 0 of 2xcsc(x)

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limit as x approaches 1 of (x^2-4)/(x+2)

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