What is the integral from 1 to 16 of 8/(sqrt(x)) ?

The integral from 1 to 16 of 8/(sqrt(x)) is 48

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 16 of 8/(sqrt(x))

\int_{1}^{16} \frac{8}{x} d x

48

Solution steps

\int_{1}^{16} \frac{8}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{1}^{16} \frac{1}{x} d x

Apply the Power Rule

= 8 [2 x^{\frac{1}{2}}]_{1}^{16}

Apply radical rule:

= 8 [2 x]_{1}^{16}

Compute the boundaries:

6

= 8 \cdot 6

Simplify

= 48

What is the integral from 1 to 16 of 8/(sqrt(x)) ?
The integral from 1 to 16 of 8/(sqrt(x)) is 48