What is the limit as t approaches 3 of (t^2-9)/(t-3) ?

The limit as t approaches 3 of (t^2-9)/(t-3) is 6

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limit as t approaches 3 of (t^2-9)/(t-3)

t \to 3 lim (\frac{t ^{2} - 9}{t - 3})

6

Solution steps

t \to 3 lim (\frac{t ^{2} - 9}{t - 3})

Simplify

\frac{t ^{2} - 9}{t - 3} : t + 3

= t \to 3 lim (t + 3)

Plug in the value

t = 3

= 3 + 3

Simplify

= 6

What is the limit as t approaches 3 of (t^2-9)/(t-3) ?
The limit as t approaches 3 of (t^2-9)/(t-3) is 6