What is the limit as x approaches 2+of ln(x-2)+pi/2 ?

The limit as x approaches 2+of ln(x-2)+pi/2 is -infinity

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limit as x approaches 2+of ln(x-2)+pi/2

x \to 2 + lim (ln (x - 2) + \frac{π}{2})

- \infty

Solution steps

x \to 2 + lim (ln (x - 2) + \frac{π}{2})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 2 + lim (ln (x - 2)) + x \to 2 + lim (\frac{π}{2})

x \to 2 + lim (ln (x - 2)) = - \infty

x \to 2 + lim (\frac{π}{2}) = \frac{π}{2}

= - \infty + \frac{π}{2}

Apply Infinity Property:

- \infty + c = - \infty

= - \infty

What is the limit as x approaches 2+of ln(x-2)+pi/2 ?
The limit as x approaches 2+of ln(x-2)+pi/2 is -infinity