y^{''}-4y^'+3y=0,y(0)=2,y^'(0)=3

Lösung

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = 2, y^{^{'}} (0) = 3

y = (2 - \frac{3}{2}) e^{3 t} + \frac{3}{2} e^{t}

Schritte zur Lösung

y^{''} (t) - 4 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = (2 - \frac{3}{2}) e^{3 t} + \frac{3}{2} e^{t}

y = (2 - \frac{3}{2}) e^{3 t} + \frac{3}{2} e^{t}

\int_{0}^{2} 5 d x

\frac{\partial}{\partial x} (x y^{9} - x^{2} y)

x \to 6 lim (x^{2} + 13)

\frac{d y}{d x} = 2 x y^{4}

x \to 3 lim (\frac{x + 3}{x ^{2} - 9})