What is the limit as x approaches 0+of x/(e^{-5/x)} ?

The limit as x approaches 0+of x/(e^{-5/x)} is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as x approaches 0+of x/(e^{-5/x)}

x \to 0 + lim (\frac{x}{e ^{- \frac{5}{x}}})

\infty

Solution steps

x \to 0 + lim (\frac{x}{e ^{- \frac{5}{x}}})

Simplify

\frac{x}{e ^{- \frac{5}{x}}} : e^{\frac{5}{x}} x

= x \to 0 + lim (e^{\frac{5}{x}} x)

Rewrite for L'Hopital

= x \to 0 + lim (\frac{e ^{\frac{5}{x}}}{\frac{1}{x}})

Apply L'Hopital's Rule

= x \to 0 + lim \frac{- \frac{5 e ^{\frac{5}{x}}}{x ^{2}}}{- \frac{1}{x ^{2}}}

Simplify

\frac{- \frac{5 e ^{\frac{5}{x}}}{x ^{2}}}{- \frac{1}{x ^{2}}} : 5 e^{\frac{5}{x}}

= x \to 0 + lim (5 e^{\frac{5}{x}})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 5 \cdot x \to 0 + lim (e^{\frac{5}{x}})

Apply the Limit Chain Rule:

\infty

= 5 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

What is the limit as x approaches 0+of x/(e^{-5/x)} ?
The limit as x approaches 0+of x/(e^{-5/x)} is infinity