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Popular Calculus >

integral from 0 to 3 of |x^2-4|

Solution

\int_{0}^{3} x^{2} - 4 d x

Solution

\frac{23}{3}

+1

Decimal

7.66666 \dots

Solution steps

\int_{0}^{3} x^{2} - 4 d x

Eliminate Absolutes

= \int_{0}^{2} - x^{2} + 4 d x + \int_{2}^{3} x^{2} - 4 d x

\int_{0}^{2} - x^{2} + 4 d x = \frac{16}{3}

\int_{2}^{3} x^{2} - 4 d x = \frac{7}{3}

= \frac{16}{3} + \frac{7}{3}

Simplify

\frac{16}{3} + \frac{7}{3} : \frac{23}{3}

= \frac{23}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of |x^2-4| ?
The integral from 0 to 3 of |x^2-4| is 23/3