limit as x approaches 0 of 1/(x+x^2)

Lösung

x \to 0 lim (\frac{1}{x + x ^{2}})

divergiert

Schritte zur Lösung

x \to 0 lim (\frac{1}{x + x ^{2}})

Wenn

x \to a - lim f (x) \neq = x \to a + lim f (x)

dann gibt es keine Grenze

x \to 0 + lim (\frac{1}{x + x ^{2}}) = \infty

x \to 0 - lim (\frac{1}{x + x ^{2}}) = - \infty

= divergiert

x \to 3 + lim (3 - x)

x \to 0 + lim (e^{\frac{1}{x}} x)

x \to - 7 - lim (f (x))

x \to 2 lim (\frac{x + 1}{2 x - 1})

x \to 1 lim (x^{9} - 1)