What is the limit as t approaches 0+of tln(t^2) ?

The limit as t approaches 0+of tln(t^2) is 0

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limit as t approaches 0+of tln(t^2)

t \to 0 + lim (t ln (t^{2}))

0

Solution steps

t \to 0 + lim (t ln (t^{2}))

Rewrite for L'Hopital

= t \to 0 + lim (\frac{ln ( t ^{2} )}{\frac{1}{t}})

Apply L'Hopital's Rule

= t \to 0 + lim (\frac{\frac{2}{t}}{- \frac{1}{t ^{2}}})

Simplify

\frac{\frac{2}{t}}{- \frac{1}{t ^{2}}} : - 2 t

= t \to 0 + lim (- 2 t)

Plug in the value

t = 0

= - 2 \cdot 0

Simplify

= 0

What is the limit as t approaches 0+of tln(t^2) ?
The limit as t approaches 0+of tln(t^2) is 0