What is the integral of 1/((x-7)(x+1)) ?

The integral of 1/((x-7)(x+1)) is 1/8 ln|x-7|-1/8 ln|x+1|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/((x-7)(x+1))

\int \frac{1}{( x - 7 ) ( x + 1 )} d x

\frac{1}{8} ln ∣ x - 7 ∣ - \frac{1}{8} ln ∣ x + 1 ∣ + C

Solution steps

\int \frac{1}{( x - 7 ) ( x + 1 )} d x

Take the partial fraction of

\frac{1}{( x - 7 ) ( x + 1 )} : \frac{1}{8 ( x - 7 )} - \frac{1}{8 ( x + 1 )}

= \int \frac{1}{8 ( x - 7 )} - \frac{1}{8 ( x + 1 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{8 ( x - 7 )} d x - \int \frac{1}{8 ( x + 1 )} d x

\int \frac{1}{8 ( x - 7 )} d x = \frac{1}{8} ln ∣ x - 7 ∣

\int \frac{1}{8 ( x + 1 )} d x = \frac{1}{8} ln ∣ x + 1 ∣

= \frac{1}{8} ln ∣ x - 7 ∣ - \frac{1}{8} ln ∣ x + 1 ∣

Add a constant to the solution

= \frac{1}{8} ln ∣ x - 7 ∣ - \frac{1}{8} ln ∣ x + 1 ∣ + C

What is the integral of 1/((x-7)(x+1)) ?
The integral of 1/((x-7)(x+1)) is 1/8 ln|x-7|-1/8 ln|x+1|+C