(dy)/(dx)=sin(3x)

Lösung

\frac{d y}{d x} = sin (3 x)

y = - \frac{1}{3} cos (3 x) + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = sin (3 x)

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = sin (3 x)

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int sin (3 x) d x

\int sin (3 x) d x = - \frac{1}{3} cos (3 x) + c_{1}

y = - \frac{1}{3} cos (3 x) + c_{1}

\frac{d y}{d x} = e^{3 x} + 8 y

\frac{\partial}{\partial y} ((x y)^{\frac{1}{2}})

\int \frac{( 8 x ^{2} + 3 x - 6 )}{( x ^{2} - 4 ) ( x + 2 )} d x

\frac{\partial}{\partial y} (2 arctan (\frac{x}{y}))

\frac{d y}{d x} = 4 y^{2} x