What is the tangent of f(x)=x^4-10x^2+9,\at x=2 ?

The tangent of f(x)=x^4-10x^2+9,\at x=2 is y=-8x+1

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tangent of f(x)=x^4-10x^2+9,\at x=2

tangent of

f (x) = x^{4} - 10 x^{2} + 9, at x = 2

y = - 8 x + 1

Solution steps

Find the tangent point:

(2, - 15)

Find the slope of

f (x) = x^{4} - 10 x^{2} + 9 : \frac{df ( x )}{d x} = 4 x^{3} - 20 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

Find the line with slope m=

- 8

and passing through

(2, - 15) : y = - 8 x + 1

y = - 8 x + 1

What is the tangent of f(x)=x^4-10x^2+9,\at x=2 ?
The tangent of f(x)=x^4-10x^2+9,\at x=2 is y=-8x+1