What is the limit as h approaches 0 of 1/(1+h^2) ?

The limit as h approaches 0 of 1/(1+h^2) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as h approaches 0 of 1/(1+h^2)

h \to 0 lim (\frac{1}{1 + h ^{2}})

1

Solution steps

h \to 0 lim (\frac{1}{1 + h ^{2}})

Plug in the value

h = 0

= \frac{1}{1 + 0 ^{2}}

Simplify

= 1

x \to \infty lim (100)

x \to 1 + lim (ln (x) - 1)

t \to 0 lim (\frac{t}{sin ( t )})

x \to 0 + lim (sin (2 x))

x \to 1 lim ((x + 1)^{2})

What is the limit as h approaches 0 of 1/(1+h^2) ?
The limit as h approaches 0 of 1/(1+h^2) is 1