What is the limit as x approaches-1 of 2^{1+ln|x|} ?

The limit as x approaches-1 of 2^{1+ln|x|} is 2

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limit as x approaches-1 of 2^{1+ln|x|}

x \to - 1 lim (2^{1 + l n ∣ x ∣})

2

Solution steps

x \to - 1 lim (2^{1 + l n ∣ x ∣})

Plug in the value

x = - 1

= 2^{1 + l n ∣ (- 1) ∣}

Simplify

2^{1 + l n ∣ - 1 ∣} : 2

= 2

What is the limit as x approaches-1 of 2^{1+ln|x|} ?
The limit as x approaches-1 of 2^{1+ln|x|} is 2