What is the limit as x approaches 9 of 1/(sqrt(x)-3) ?

The limit as x approaches 9 of 1/(sqrt(x)-3) is diverges

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limit as x approaches 9 of 1/(sqrt(x)-3)

x \to 9 lim (\frac{1}{x - 3})

diverges

Solution steps

x \to 9 lim (\frac{1}{x - 3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 9 + lim (\frac{1}{x - 3}) = \infty

x \to 9 - lim (\frac{1}{x - 3}) = - \infty

= diverges

What is the limit as x approaches 9 of 1/(sqrt(x)-3) ?
The limit as x approaches 9 of 1/(sqrt(x)-3) is diverges