What is the limit as x approaches 0 of ln(1-e^x) ?

The limit as x approaches 0 of ln(1-e^x) is Does not exist

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as x approaches 0 of ln(1-e^x)

x \to 0 lim (ln (1 - e^{x}))

Does not exist

Solution steps

x \to 0 lim (ln (1 - e^{x}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (ln (1 - e^{x})) =

Does not exist

x \to 0 - lim (ln (1 - e^{x})) = - \infty

= Does not exist

What is the limit as x approaches 0 of ln(1-e^x) ?
The limit as x approaches 0 of ln(1-e^x) is Does not exist