What is the limit as x approaches 4 of (2x)/(x^2-16) ?

The limit as x approaches 4 of (2x)/(x^2-16) is diverges

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limit as x approaches 4 of (2x)/(x^2-16)

x \to 4 lim (\frac{2 x}{x ^{2} - 16})

diverges

Solution steps

x \to 4 lim (\frac{2 x}{x ^{2} - 16})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (\frac{2 x}{x ^{2} - 16}) = \infty

x \to 4 - lim (\frac{2 x}{x ^{2} - 16}) = - \infty

= diverges

What is the limit as x approaches 4 of (2x)/(x^2-16) ?
The limit as x approaches 4 of (2x)/(x^2-16) is diverges