What is the limit as t approaches 3 of (t-3)/(t^2-9) ?

The limit as t approaches 3 of (t-3)/(t^2-9) is 1/6

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limit as t approaches 3 of (t-3)/(t^2-9)

t \to 3 lim (\frac{t - 3}{t ^{2} - 9})

\frac{1}{6}

Decimal

0.16666 \dots

Solution steps

t \to 3 lim (\frac{t - 3}{t ^{2} - 9})

Simplify

\frac{t - 3}{t ^{2} - 9} : \frac{1}{t + 3}

= t \to 3 lim (\frac{1}{t + 3})

Plug in the value

t = 3

= \frac{1}{3 + 3}

Simplify

= \frac{1}{6}

What is the limit as t approaches 3 of (t-3)/(t^2-9) ?
The limit as t approaches 3 of (t-3)/(t^2-9) is 1/6