What is the limit as x approaches 0+of sin(1/x)x ?

The limit as x approaches 0+of sin(1/x)x is 0

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limit as x approaches 0+of sin(1/x)x

x \to 0 + lim (sin (\frac{1}{x}) x)

0

Solution steps

x \to 0 + lim (sin (\frac{1}{x}) x)

Apply the Squeeze Theorem:

0

= 0

x \to 2 lim (\frac{( 3 )}{( x + 2 )})

u \to 1 lim (\frac{u + 1}{u ^{2} - 1})

x \to \infty lim (x r x)

x \to 0 lim (3 x + 6)

x \to \infty lim (\frac{x + 7}{7 + 7 ^{x + 1} ( x + 6 )})

What is the limit as x approaches 0+of sin(1/x)x ?
The limit as x approaches 0+of sin(1/x)x is 0