What is the limit as x approaches 0 of (4x^2+16-20x)/(-40+5x^2-10x) ?

The limit as x approaches 0 of (4x^2+16-20x)/(-40+5x^2-10x) is -2/5

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limit as x approaches 0 of (4x^2+16-20x)/(-40+5x^2-10x)

x \to 0 lim (\frac{4 x ^{2} + 16 - 20 x}{- 40 + 5 x ^{2} - 10 x})

- \frac{2}{5}

Decimal

- 0.4

Solution steps

x \to 0 lim (\frac{4 x ^{2} + 16 - 20 x}{- 40 + 5 x ^{2} - 10 x})

Plug in the value

x = 0

= \frac{4 \cdot 0 ^{2} + 16 - 20 \cdot 0}{- 40 + 5 \cdot 0 ^{2} - 10 \cdot 0}

Simplify

\frac{4 \cdot 0 ^{2} + 16 - 20 \cdot 0}{- 40 + 5 \cdot 0 ^{2} - 10 \cdot 0} : - \frac{2}{5}

= - \frac{2}{5}

What is the limit as x approaches 0 of (4x^2+16-20x)/(-40+5x^2-10x) ?
The limit as x approaches 0 of (4x^2+16-20x)/(-40+5x^2-10x) is -2/5