What is the limit as x approaches 0+of x^{1/4}*ln(x) ?

The limit as x approaches 0+of x^{1/4}*ln(x) is 0

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limit as x approaches 0+of x^{1/4}*ln(x)

x \to 0 + lim (x^{\frac{1}{4}} \cdot ln (x))

0

Solution steps

x \to 0 + lim (x^{\frac{1}{4}} ln (x))

Rewrite for L'Hopital

= x \to 0 + lim (\frac{ln ( x )}{\frac{1}{x ^{\frac{1}{4}}}})

Apply L'Hopital's Rule

= x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{1}{4 x ^{\frac{5}{4}}}})

Simplify

\frac{\frac{1}{x}}{- \frac{1}{4 x ^{\frac{5}{4}}}} : - 4 x^{\frac{1}{4}}

= x \to 0 + lim (- 4 x^{\frac{1}{4}})

Plug in the value

x = 0

= - 4 \cdot 0^{\frac{1}{4}}

Simplify

= 0

What is the limit as x approaches 0+of x^{1/4}*ln(x) ?
The limit as x approaches 0+of x^{1/4}*ln(x) is 0