What is the derivative of log_{10}(1+x) ?

The derivative of log_{10}(1+x) is 1/(ln(10)(1+x))

What is the first derivative of log_{10}(1+x) ?

The first derivative of log_{10}(1+x) is 1/(ln(10)(1+x))

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derivative of

lo g_{10} (1 + x)

\frac{1}{ln ( 10 ) ( 1 + x )}

Solution steps

\frac{d}{d x} (lo g_{10} (1 + x))

Apply log rule:

lo g_{a} (b) = \frac{ln ( b )}{ln ( a )}

= \frac{d}{d x} (\frac{ln ( 1 + x )}{ln ( 10 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{ln ( 10 )} \frac{d}{d x} (ln (1 + x))

Apply the chain rule:

\frac{1}{1 + x} \frac{d}{d x} (1 + x)

= \frac{1}{1 + x} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= \frac{1}{ln ( 10 )} \cdot \frac{1}{1 + x} \cdot 1

Simplify

\frac{1}{ln ( 10 )} \cdot \frac{1}{1 + x} \cdot 1 : \frac{1}{ln ( 10 ) ( 1 + x )}

= \frac{1}{ln ( 10 ) ( 1 + x )}

What is the derivative of log_{10}(1+x) ?
The derivative of log_{10}(1+x) is 1/(ln(10)(1+x))
What is the first derivative of log_{10}(1+x) ?
The first derivative of log_{10}(1+x) is 1/(ln(10)(1+x))