What is the d/(d{f)}(({f}+2)/({g)}) ?

The d/(d{f)}(({f}+2)/({g)}) is 1/({g)}

What is the first d/(d{f)}(({f}+2)/({g)}) ?

The first d/(d{f)}(({f}+2)/({g)}) is 1/({g)}

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\frac{d}{d f} (\frac{f + 2}{g})

\frac{1}{g}

Solution steps

\frac{d}{d f} (\frac{f + 2}{g})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{g} \frac{d}{d f} (f + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{g} (\frac{d}{d f} (f) + \frac{d}{d f} (2))

\frac{d}{d f} (f) = 1

\frac{d}{d f} (2) = 0

= \frac{1}{g} (1 + 0)

Simplify

= \frac{1}{g}

What is the d/(d{f)}(({f}+2)/({g)}) ?
The d/(d{f)}(({f}+2)/({g)}) is 1/({g)}
What is the first d/(d{f)}(({f}+2)/({g)}) ?
The first d/(d{f)}(({f}+2)/({g)}) is 1/({g)}