What is the derivative of 2x^3-4x^5+8+7x^2 ?

The derivative of 2x^3-4x^5+8+7x^2 is -20x^4+6x^2+14x

What is the first derivative of 2x^3-4x^5+8+7x^2 ?

The first derivative of 2x^3-4x^5+8+7x^2 is -20x^4+6x^2+14x

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derivative of

2 x^{3} - 4 x^{5} + 8 + 7 x^{2}

- 20 x^{4} + 6 x^{2} + 14 x

Solution steps

\frac{d}{d x} (2 x^{3} - 4 x^{5} + 8 + 7 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (4 x^{5}) + \frac{d}{d x} (8) + \frac{d}{d x} (7 x^{2})

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4 x^{5}) = 20 x^{4}

\frac{d}{d x} (8) = 0

\frac{d}{d x} (7 x^{2}) = 14 x

= 6 x^{2} - 20 x^{4} + 0 + 14 x

Simplify

= - 20 x^{4} + 6 x^{2} + 14 x

What is the derivative of 2x^3-4x^5+8+7x^2 ?
The derivative of 2x^3-4x^5+8+7x^2 is -20x^4+6x^2+14x
What is the first derivative of 2x^3-4x^5+8+7x^2 ?
The first derivative of 2x^3-4x^5+8+7x^2 is -20x^4+6x^2+14x