What is the derivative of g(z)=10tan(z)-2cot(z) ?

The derivative of g(z)=10tan(z)-2cot(z) is 10sec^2(z)+2csc^2(z)

What is the first derivative of g(z)=10tan(z)-2cot(z) ?

The first derivative of g(z)=10tan(z)-2cot(z) is 10sec^2(z)+2csc^2(z)

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derivative of

g (z) = 10 tan (z) - 2 cot (z)

10 sec^{2} (z) + 2 csc^{2} (z)

Solution steps

\frac{d}{d z} (10 tan (z) - 2 cot (z))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d z} (10 tan (z)) - \frac{d}{d z} (2 cot (z))

\frac{d}{d z} (10 tan (z)) = 10 sec^{2} (z)

\frac{d}{d z} (2 cot (z)) = - 2 csc^{2} (z)

= 10 sec^{2} (z) - (- 2 csc^{2} (z))

Simplify

= 10 sec^{2} (z) + 2 csc^{2} (z)

What is the derivative of g(z)=10tan(z)-2cot(z) ?
The derivative of g(z)=10tan(z)-2cot(z) is 10sec^2(z)+2csc^2(z)
What is the first derivative of g(z)=10tan(z)-2cot(z) ?
The first derivative of g(z)=10tan(z)-2cot(z) is 10sec^2(z)+2csc^2(z)