What is the d/(da)(-4sin^2(a)+5-4cos^2(a)) ?

The d/(da)(-4sin^2(a)+5-4cos^2(a)) is 0

What is the first d/(da)(-4sin^2(a)+5-4cos^2(a)) ?

The first d/(da)(-4sin^2(a)+5-4cos^2(a)) is 0

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\frac{d}{d a} (- 4 sin^{2} (a) + 5 - 4 cos^{2} (a))

0

Solution steps

\frac{d}{d a} (- 4 sin^{2} (a) + 5 - 4 cos^{2} (a))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d a} (4 sin^{2} (a)) + \frac{d}{d a} (5) - \frac{d}{d a} (4 cos^{2} (a))

\frac{d}{d a} (4 sin^{2} (a)) = 4 sin (2 a)

\frac{d}{d a} (5) = 0

\frac{d}{d a} (4 cos^{2} (a)) = - 4 sin (2 a)

= - 4 sin (2 a) + 0 - (- 4 sin (2 a))

Simplify

= 0

What is the d/(da)(-4sin^2(a)+5-4cos^2(a)) ?
The d/(da)(-4sin^2(a)+5-4cos^2(a)) is 0
What is the first d/(da)(-4sin^2(a)+5-4cos^2(a)) ?
The first d/(da)(-4sin^2(a)+5-4cos^2(a)) is 0