What is the derivative of 4x^3-9x^2+28x-68 ?

The derivative of 4x^3-9x^2+28x-68 is 12x^2-18x+28

What is the first derivative of 4x^3-9x^2+28x-68 ?

The first derivative of 4x^3-9x^2+28x-68 is 12x^2-18x+28

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derivative of

4 x^{3} - 9 x^{2} + 28 x - 68

12 x^{2} - 18 x + 28

Solution steps

\frac{d}{d x} (4 x^{3} - 9 x^{2} + 28 x - 68)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (9 x^{2}) + \frac{d}{d x} (28 x) - \frac{d}{d x} (68)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (28 x) = 28

\frac{d}{d x} (68) = 0

= 12 x^{2} - 18 x + 28 - 0

Simplify

= 12 x^{2} - 18 x + 28

What is the derivative of 4x^3-9x^2+28x-68 ?
The derivative of 4x^3-9x^2+28x-68 is 12x^2-18x+28
What is the first derivative of 4x^3-9x^2+28x-68 ?
The first derivative of 4x^3-9x^2+28x-68 is 12x^2-18x+28