What is the integral of (3x-sin(x)) ?

The integral of (3x-sin(x)) is (3x^2)/2+cos(x)+C

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integral of (3x-sin(x))

\int (3 x - sin (x)) d x

\frac{3 x ^{2}}{2} + cos (x) + C

Solution steps

\int 3 x - sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x d x - \int sin (x) d x

\int 3 x d x = \frac{3 x ^{2}}{2}

\int sin (x) d x = - cos (x)

= \frac{3 x ^{2}}{2} - (- cos (x))

Simplify

= \frac{3 x ^{2}}{2} + cos (x)

Add a constant to the solution

= \frac{3 x ^{2}}{2} + cos (x) + C

What is the integral of (3x-sin(x)) ?
The integral of (3x-sin(x)) is (3x^2)/2+cos(x)+C