What is the derivative of e^sinx+x(tan(x))^2 ?

The derivative of e^sinx+x(tan(x))^2 is ine^sx

What is the first derivative of e^sinx+x(tan(x))^2 ?

The first derivative of e^sinx+x(tan(x))^2 is ine^sx

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derivative of

e^{s} in x + x (tan (x))^{2}

in e^{s} x

Solution steps

\frac{d}{d s} (e^{s} in x + x (tan (x))^{2})

Treat

i, n, x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d s} (e^{s} in x) + \frac{d}{d s} (x (tan (x))^{2})

\frac{d}{d s} (e^{s} in x) = in x e^{s}

\frac{d}{d s} (x (tan (x))^{2}) = 0

= in x e^{s} + 0

Simplify

= in e^{s} x

What is the derivative of e^sinx+x(tan(x))^2 ?
The derivative of e^sinx+x(tan(x))^2 is ine^sx
What is the first derivative of e^sinx+x(tan(x))^2 ?
The first derivative of e^sinx+x(tan(x))^2 is ine^sx