What is the derivative of 64(2+x)^1 ?

The derivative of 64(2+x)^1 is 64

What is the first derivative of 64(2+x)^1 ?

The first derivative of 64(2+x)^1 is 64

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derivative of

64 (2 + x)^{1}

64

Solution steps

\frac{d}{d x} (64 (2 + x)^{1})

Simplify

64 (2 + x)^{1} : 64 (2 + x)

= \frac{d}{d x} (64 (2 + x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 64 \frac{d}{d x} (2 + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 64 (\frac{d}{d x} (2) + \frac{d x}{d x})

\frac{d}{d x} (2) = 0

\frac{d x}{d x} = 1

= 64 (0 + 1)

Simplify

= 64

What is the derivative of 64(2+x)^1 ?
The derivative of 64(2+x)^1 is 64
What is the first derivative of 64(2+x)^1 ?
The first derivative of 64(2+x)^1 is 64