What is the derivative of f(x)=(x+2)^2-3x ?

The derivative of f(x)=(x+2)^2-3x is 2x+1

What is the first derivative of f(x)=(x+2)^2-3x ?

The first derivative of f(x)=(x+2)^2-3x is 2x+1

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derivative of

f (x) = (x + 2)^{2} - 3 x

2 x + 1

Solution steps

\frac{d}{d x} ((x + 2)^{2} - 3 x)

Simplify

(x + 2)^{2} - 3 x : x^{2} + x + 4

= \frac{d}{d x} (x^{2} + x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (4) = 0

= 2 x + 1 + 0

Simplify

= 2 x + 1

What is the derivative of f(x)=(x+2)^2-3x ?
The derivative of f(x)=(x+2)^2-3x is 2x+1
What is the first derivative of f(x)=(x+2)^2-3x ?
The first derivative of f(x)=(x+2)^2-3x is 2x+1