What is the derivative of y= x/((x^2-3)) ?

The derivative of y= x/((x^2-3)) is (-x^2-3)/((x^2-3)^2)

What is the first derivative of y= x/((x^2-3)) ?

The first derivative of y= x/((x^2-3)) is (-x^2-3)/((x^2-3)^2)

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derivative of

y = \frac{x}{( x ^{2} - 3 )}

\frac{- x ^{2} - 3}{( x ^{2} - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{x ^{2} - 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( x ^{2} - 3 ) - \frac{d}{d x} ( x ^{2} - 3 ) x}{( x ^{2} - 3 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} - 3) = 2 x

= \frac{1 \cdot ( x ^{2} - 3 ) - 2 xx}{( x ^{2} - 3 ) ^{2}}

1 \cdot (x^{2} - 3) - 2 xx = - x^{2} - 3

= \frac{- x ^{2} - 3}{( x ^{2} - 3 ) ^{2}}

What is the derivative of y= x/((x^2-3)) ?
The derivative of y= x/((x^2-3)) is (-x^2-3)/((x^2-3)^2)
What is the first derivative of y= x/((x^2-3)) ?
The first derivative of y= x/((x^2-3)) is (-x^2-3)/((x^2-3)^2)