What is the derivative of x^2+y^2-6x+8y ?

The derivative of x^2+y^2-6x+8y is 2x-6

What is the first derivative of x^2+y^2-6x+8y ?

The first derivative of x^2+y^2-6x+8y is 2x-6

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derivative of

x^{2} + y^{2} - 6 x + 8 y

2 x - 6

Solution steps

\frac{d}{d x} (x^{2} + y^{2} - 6 x + 8 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (y^{2}) - \frac{d}{d x} (6 x) + \frac{d}{d x} (8 y)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{2}) = 0

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (8 y) = 0

= 2 x + 0 - 6 + 0

Simplify

= 2 x - 6

What is the derivative of x^2+y^2-6x+8y ?
The derivative of x^2+y^2-6x+8y is 2x-6
What is the first derivative of x^2+y^2-6x+8y ?
The first derivative of x^2+y^2-6x+8y is 2x-6