What is the derivative of x^3+x^2+x-4 ?

The derivative of x^3+x^2+x-4 is 3x^2+2x+1

What is the first derivative of x^3+x^2+x-4 ?

The first derivative of x^3+x^2+x-4 is 3x^2+2x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

x^{3} + x^{2} + x - 4

3 x^{2} + 2 x + 1

Solution steps

\frac{d}{d x} (x^{3} + x^{2} + x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (4) = 0

= 3 x^{2} + 2 x + 1 - 0

Simplify

= 3 x^{2} + 2 x + 1

What is the derivative of x^3+x^2+x-4 ?
The derivative of x^3+x^2+x-4 is 3x^2+2x+1
What is the first derivative of x^3+x^2+x-4 ?
The first derivative of x^3+x^2+x-4 is 3x^2+2x+1