What is the first derivative of 3+4t ?

The first derivative of 3+4t is 4

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derivative of 3+4t

derivative of

3 + 4 t

4

Solution steps

\frac{d}{d t} (3 + 4 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3) + \frac{d}{d t} (4 t)

\frac{d}{d t} (3) = 0

\frac{d}{d t} (4 t) = 4

= 0 + 4

Simplify

= 4

d er i v a t i v e \frac{x}{x ^{3} + 1}

d er i v a t i v e a^{3} - 3

d er i v a t i v e y = \frac{( x ^{2} + 1 )}{x ^{3}}

d er i v a t i v e t^{2} + 1

d er i v a t i v e x^{3} - 3^{x}