What is the derivative of 1/n ?

The derivative of 1/n is -1/(n^2)

What is the first derivative of 1/n ?

The first derivative of 1/n is -1/(n^2)

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derivative of

\frac{1}{n}

- \frac{1}{n ^{2}}

Solution steps

\frac{d}{d n} (\frac{1}{n})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d n} (n^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 1 \cdot n^{- 1 - 1}

Simplify

- 1 \cdot n^{- 1 - 1} : - \frac{1}{n ^{2}}

= - \frac{1}{n ^{2}}

d er i v a t i v e (3 x^{2} + 7) (6 x + 3)

d er i v a t i v e (x^{2} - y^{2})^{\frac{1}{2}}

d er i v a t i v e \frac{( ( x ^{6} ) - 1 )}{( ( x ^{6} ) + 1 )}

d er i v a t i v e y = 3 cos (x) + 7 e x + ln (x^{2} + 1)

d er i v a t i v e f (x) = \frac{4 x - 1}{x}