What is derivative of x^2=2+t ?

The answer to derivative of x^2=2+t is (dx)/(dt)= 1/(2x)

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derivative of x^2=2+t

derivative of

x^{2} = 2 + t

\frac{d x}{d t} = \frac{1}{2 x}

Solution steps

x^{2} = 2 + t

Treat

x

x (t)

Differentiate both sides:

2 x \frac{d x}{d t} = 1

Isolate

\frac{d x}{d t} : \frac{d x}{d t} = \frac{1}{2 x}

\frac{d x}{d t} = \frac{1}{2 x}

d er i v a t i v e x = (1 - y^{2})^{\frac{1}{2}}

d er i v a t i v e 2 x^{2} + 2 y - 2 x y = 4

d er i v a t i v e x^{2} + 2 x y = y^{2}

d er i v a t i v e x^{3} + x^{2} y + 7 x y^{2} + y^{3} = 81

d er i v a t i v e y - 4 = 2 (x - 1)^{2}

What is derivative of x^2=2+t ?
The answer to derivative of x^2=2+t is (dx)/(dt)= 1/(2x)