What is the integral of (x^{-1})/(x^2) ?

The integral of (x^{-1})/(x^2) is -1/(2x^2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (x^{-1})/(x^2)

integral

\frac{x ^{- 1}}{x ^{2}}

- \frac{1}{2 x ^{2}} + C

Solution steps

\int \frac{x ^{- 1}}{x ^{2}} d x

Simplify

\frac{x ^{- 1}}{x ^{2}} : \frac{1}{x ^{3}}

= \int \frac{1}{x ^{3}} d x

Apply the Power Rule

= - \frac{1}{2 x ^{2}}

Add a constant to the solution

= - \frac{1}{2 x ^{2}} + C

What is the integral of (x^{-1})/(x^2) ?
The integral of (x^{-1})/(x^2) is -1/(2x^2)+C