What is the integral of x/((x^2+a^2)) ?

The integral of x/((x^2+a^2)) is 1/2 ln|x^2+a^2|+C

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integral of x/((x^2+a^2))

integral

\frac{x}{( x ^{2} + a ^{2} )}

\frac{1}{2} ln x^{2} + a^{2} + C

Solution steps

\int \frac{x}{x ^{2} + a ^{2}} d x

Apply u-substitution

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} ln ∣ u ∣

Substitute back

u = x^{2} + a^{2}

= \frac{1}{2} ln x^{2} + a^{2}

Add a constant to the solution

= \frac{1}{2} ln x^{2} + a^{2} + C

in t e g r a l \frac{1}{( x - 1 )}

in t e g r a l x^{3} (e^{x})^{2}

in t e g r a l \frac{1}{( x ^{3} + 1 )}

in t e g r a l \frac{( x - 1 )}{( x + 1 ) ^{2}}

in t e g r a l - x^{- 2}

What is the integral of x/((x^2+a^2)) ?
The integral of x/((x^2+a^2)) is 1/2 ln|x^2+a^2|+C