What is the integral of (-2)/(x^2) ?

The integral of (-2)/(x^2) is 2/x+C

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integral of (-2)/(x^2)

integral

\frac{- 2}{x ^{2}}

\frac{2}{x} + C

Solution steps

\int \frac{- 2}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

= - 2 (- \frac{1}{x})

Simplify

- 2 (- \frac{1}{x}) : \frac{2}{x}

= \frac{2}{x}

Add a constant to the solution

= \frac{2}{x} + C

in t e g r a l \frac{2}{e ^{x}}

in t e g r a l cos (\frac{1}{x})

in t e g r a l y = - sin^{3} (x)

in t e g r a l \frac{x}{( x ^{2} + 4 )}

in t e g r a l x^{8} \cdot ln (x)