What is the solution for y^{''}+4y^'+3y=4e^{-t},y(0)=0,y^'(0)=2 ?

The solution for y^{''}+4y^'+3y=4e^{-t},y(0)=0,y^'(0)=2 is y=2e^{-t}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+4y^'+3y=4e^{-t},y(0)=0,y^'(0)=2

y^{^{''}} + 4 y^{^{'}} + 3 y = 4 e^{- t}, y (0) = 0, y^{^{'}} (0) = 2

y = 2 e^{- t} t

Solution steps

y^{''} (t) + 4 y^{'} (t) + 3 y = 4 e^{- t}

Solve linear ODE:

y = 2 e^{- t} t

y = 2 e^{- t} t

What is the solution for y^{''}+4y^'+3y=4e^{-t},y(0)=0,y^'(0)=2 ?
The solution for y^{''}+4y^'+3y=4e^{-t},y(0)=0,y^'(0)=2 is y=2e^{-t}t