What is the integral of e^x*sin^2(x) ?

The integral of e^x*sin^2(x) is e^xsin^2(x)+2/5 e^xcos(2x)-1/5 e^xsin(2x)+C

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integral of e^x*sin^2(x)

integral

e^{x} \cdot sin^{2} (x)

e^{x} sin^{2} (x) + \frac{2}{5} e^{x} cos (2 x) - \frac{1}{5} e^{x} sin (2 x) + C

Solution steps

\int e^{x} sin^{2} (x) d x

Apply Integration By Parts

= sin^{2} (x) e^{x} - \int sin (2 x) e^{x} d x

\int sin (2 x) e^{x} d x = - \frac{2 e ^{x} cos ( 2 x )}{5} + \frac{e ^{x} sin ( 2 x )}{5}

= sin^{2} (x) e^{x} - (- \frac{2 e ^{x} cos ( 2 x )}{5} + \frac{e ^{x} sin ( 2 x )}{5})

Simplify

sin^{2} (x) e^{x} - (- \frac{2 e ^{x} cos ( 2 x )}{5} + \frac{e ^{x} sin ( 2 x )}{5}) : e^{x} sin^{2} (x) + \frac{2}{5} e^{x} cos (2 x) - \frac{1}{5} e^{x} sin (2 x)

= e^{x} sin^{2} (x) + \frac{2}{5} e^{x} cos (2 x) - \frac{1}{5} e^{x} sin (2 x)

Add a constant to the solution

= e^{x} sin^{2} (x) + \frac{2}{5} e^{x} cos (2 x) - \frac{1}{5} e^{x} sin (2 x) + C

in t e g r a l x^{2} - 1

in t e g r a l \frac{x}{( x ^{3} + 1 )}

in t e g r a l \frac{1}{( x - x ^{2} )}

in t e g r a l sin (2 x^{2})

in t e g r a l \frac{( x + 1 ) ^{3}}{x ^{3}}

What is the integral of e^x*sin^2(x) ?
The integral of e^x*sin^2(x) is e^xsin^2(x)+2/5 e^xcos(2x)-1/5 e^xsin(2x)+C